It is not to solve so much as to see the number of solutions and whether there is a real solution to the equation. b2 - 4(a)(c) A positive answer = two real solutions. A negative answer = no real solution ( complex solution i ) If zero as the answer there is one real solution.
Zero is an acceptable value for a variable. As a general rule, if you solve an equation and get x equals zero, that's just what it is: zero. There is one solution. Example: 10x +1 = 5x +1 5x = 1 - 1 5x = 0 x = 0 There is one solution, zero. If you solve for x and get two solutions, such as 2 and 0, there are two answers. Later on, if you've studied domain and range (the numbers you can use for x so that the equation is still defined, (i.e. not 1/0, or the square root of negative 1), you may find that x = 0 does not always work. You need to check first, to see if zero is in the domain, before you say it's an answer.
Multiplication:- If: f/3 = 0.27 Then by multiplying both sides by 3: f = 0.81
If you set a function equal to zero and solve for x, then you are finding where the function crosses the x-axis.
To find the points of intersection on the x-axis, set y equal to zero and solve for x. So, 8x^2 - 26x + 15 = 0. This is a quadratic equation that can be factored or solved using the quadratic formula. Once you find the values of x, those are the points of intersection on the x-axis.
If it is a linear function, it is quite easy to solve the equation explicitly, using standard methods of equation-solving. For example, if you have "y" as a function of "x", you would have to solve the variable for "x".
It can be solved by using the quadratic equation formula.
-- Take the equation. -- Say to yourself, "At the x-intercept, y=0". Set 'y' equal to zero, solve the equation for 'x', and you have the x-intercept. -- Take the original equation again. -- Say to yourself, "At the y-intercept, x=0". Set 'x' equal to zero, solve the equation for 'y', and you have the y-intercept.
If the discriminant of a quadratic equation is less than zero then it will not have any real roots.
Set 'x' equal to zero, and solve the remaining equation for 'y'.
-- Factor the left side of the equation. -- Set one factor equal to zero, and solve it for 'x'. That gives you one solution to the equation. -- Set the other factor to zero, and solve it for 'x'. That gives you the other solution to the equation. -- If you don't get x=2 and x=-8/3 then repeat the previous steps, because you made a mistake the first time.
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
To find the multiplicative inverse, you would have to solve the equation 0 times x = 1. Since any number times 0 is zero, this equation has no solution.
To solve for n in the Van Der Waals equation, you can rearrange the equation to isolate n. The Van Der Waals equation is ((P + a(\frac{n}{V})^2)(V - nb) = nRT). By manipulating this equation, you can solve for n by setting it equal to zero and applying the quadratic formula.
That depends how you plan to solve it - there are several methods. But usually you would start by arranging the equation in "standard form", meaning that on the right of the equal sign, you only have zero.
Well, that's one method to solve the quadratic equation. Here is an example (using the symbol "^" for power): solve x^2 - 5x + 6 = 0 Step 1: Convert the equation to a form in which the right side is equal to zero. (Already done in this example.) Step 2: Factor the left side. In this case, (x - 3) (x - 2) = 0 Step 3: Use the fact that if a product is zero, at least one of its factors must be zero. This lets you convert the equation to two equations; x - 3 = 0 OR x - 2 = 0 Step 4: Solve each of the two equations.
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.