Zero is an acceptable value for a variable.
As a general rule, if you solve an equation and get x equals zero, that's just what it is: zero. There is one solution.
Example: 10x +1 = 5x +1
5x = 1 - 1
5x = 0
x = 0
There is one solution, zero.
If you solve for x and get two solutions, such as 2 and 0, there are two answers.
Later on, if you've studied domain and range (the numbers you can use for x so that the equation is still defined, (i.e. not 1/0, or the square root of negative 1), you may find that x = 0 does not always work. You need to check first, to see if zero is in the domain, before you say it's an answer.
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of Ī, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nĪ, where n is an integer.
Yes.
x = 0 or x = 2
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
0
True because in both equations x = 0 or x = -4
The only solution to this is x=0.
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
solution: y = 0 x = -1
(x, y) = (-6, 0)
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
(x-6)(x+4) = 0 x = 6 or x = -4
x = -1 or x = 5