Equations: 2x-3y = 4 and 5x+2y = 1
Multiply all terms in 1st equation by 5 and all terms in 2nd equation by 2:-
So: 10x-15y = 20 and 10x+4y = 2
Subtract the 2nd equation from the 1st equation: -19y = 18 => y = -18/19
By substitution the solutions are: x = 11/19 and y = -18/19
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
Add the two equations together. This will give you a single equation in one variable. Solve this - it should give you two solutions. Then replace the corresponding variable for each of the solutions in any of the original equations.
Through a process of elimination and substitution the solutions are s = 8 and x = 5
They are simultaneous equations and their solutions are x = 41 and y = -58
The solutions are: x = 4, y = 2 and x = -4, y = -2
Simultaneous equations.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
1
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
Without any equality signs the given expressions can't be considered to be simultaneous equations and so therefore no solutions are possible.
Just one.