assuming the bases are the same, you can factor the log out, so you get:
x^2 = 2 + 3x-4 (note that 2logx can be rewritten as logx^2 )
x^2 - 3x +2 = 0
You can factor this out: (x-1)(x-2) = 0
so x must be one or x is two --> X=1 V X=2
logx^2=2 2logx=2 logx=1 10^1=x x=10
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
(1/4)x^2(2logx-1) + c
2logx-log5=-2 logx^2-log5=-2 log(x^2 / 5)=-2 x^2 / 5 = 10^-2 x^2=5(1/100) x^2=1/20 x=√(1/20)
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