How do you solve this logarithmic equation 2logX equals log2 plus log3X-4?

Answer 1

assuming the bases are the same, you can factor the log out, so you get:

x^2 = 2 + 3x-4 (note that 2logx can be rewritten as logx^2 )
x^2 - 3x +2 = 0


You can factor this out: (x-1)(x-2) = 0


so x must be one or x is two --> X=1 V X=2