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How do you solve this logarithmic equation 2logX equals log2 plus log3X-4?

Weaselmonger ∙

Lvl 1

∙ 16y ago

Updated: 4/28/2022

assuming the bases are the same, you can factor the log out, so you get:

x^2 = 2 + 3x-4 (note that 2logx can be rewritten as logx^2 )
x^2 - 3x +2 = 0

You can factor this out: (x-1)(x-2) = 0

so x must be one or x is two --> X=1 V X=2

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∙ 16y ago

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