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What else can I help you with?
What is the differntial of logX wrt X?
d/dx ( log x) = 1/x
How do you integrate x secx?
To integrate ( x \sec x ), you can use integration by parts. Let ( u = x ) and ( dv = \sec x , dx ). Then, ( du = dx ) and ( v = \ln |\sec x + \tan x| ). Applying the integration by parts formula, you get: [ \int x \sec x , dx = x \ln |\sec x + \tan x| - \int \ln |\sec x + \tan x| , dx + C ] where ( C ) is the constant of integration. The second integral may require further techniques to evaluate.
What is the anti-derivative of ln x?
The anti-derivative of ( \ln x ) can be found using integration by parts. Let ( u = \ln x ) and ( dv = dx ), then ( du = \frac{1}{x} dx ) and ( v = x ). Applying integration by parts, we get: [ \int \ln x , dx = x \ln x - \int x \cdot \frac{1}{x} , dx = x \ln x - x + C, ] where ( C ) is the constant of integration. Thus, the anti-derivative of ( \ln x ) is ( x \ln x - x + C ).
What is x if negative log x equals 21.1?
-logx=21.1 logx=-21.1 e^-21.1=x
Integration of xtanx?
To integrate ( x \tan(x) ), we can use integration by parts. Let ( u = x ) and ( dv = \tan(x) , dx ). This gives ( du = dx ) and ( v = -\ln|\cos(x)| ). Applying the integration by parts formula ( \int u , dv = uv - \int v , du ), we obtain: [ \int x \tan(x) , dx = -x \ln|\cos(x)| + \int \ln|\cos(x)| , dx + C ] The integral ( \int \ln|\cos(x)| , dx ) does not have a simple closed form, so the final result may be expressed in terms of this integral along with the logarithmic term.
What is the differntial of logX wrt X?
d/dx ( log x) = 1/x
What is the antiderivative of logx?
X(logX-1) + C
How do you integrate x secx?
To integrate ( x \sec x ), you can use integration by parts. Let ( u = x ) and ( dv = \sec x , dx ). Then, ( du = dx ) and ( v = \ln |\sec x + \tan x| ). Applying the integration by parts formula, you get: [ \int x \sec x , dx = x \ln |\sec x + \tan x| - \int \ln |\sec x + \tan x| , dx + C ] where ( C ) is the constant of integration. The second integral may require further techniques to evaluate.
Logx to the 2nd power equals 2 solve for x?
logx^2=2 2logx=2 logx=1 10^1=x x=10
What is integration of 1 by dx?
The integral of f'(x) = 1 is f(x) = x + c
What is the anti-derivative of ln x?
The anti-derivative of ( \ln x ) can be found using integration by parts. Let ( u = \ln x ) and ( dv = dx ), then ( du = \frac{1}{x} dx ) and ( v = x ). Applying integration by parts, we get: [ \int \ln x , dx = x \ln x - \int x \cdot \frac{1}{x} , dx = x \ln x - x + C, ] where ( C ) is the constant of integration. Thus, the anti-derivative of ( \ln x ) is ( x \ln x - x + C ).
What is the integral of the derivative with respect to x of a function of x with respect to x?
∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
What is x if negative log x equals 21.1?
-logx=21.1 logx=-21.1 e^-21.1=x
Y equals log x If y equals 10 then what is x?
y=logx y=10 logx= 10 10logx = 10log1 logx = log1 x = 1 //NajN
Integration of xtanx?
To integrate ( x \tan(x) ), we can use integration by parts. Let ( u = x ) and ( dv = \tan(x) , dx ). This gives ( du = dx ) and ( v = -\ln|\cos(x)| ). Applying the integration by parts formula ( \int u , dv = uv - \int v , du ), we obtain: [ \int x \tan(x) , dx = -x \ln|\cos(x)| + \int \ln|\cos(x)| , dx + C ] The integral ( \int \ln|\cos(x)| , dx ) does not have a simple closed form, so the final result may be expressed in terms of this integral along with the logarithmic term.
Integration formula of second puc syllabus?
The integration formulas covered in the second PUC syllabus primarily include basic integration techniques such as integration of power functions, trigonometric functions, exponential functions, and logarithmic functions. Key formulas include ∫ x^n dx = (x^(n+1))/(n+1) + C for n ≠ -1, ∫ sin(x) dx = -cos(x) + C, and ∫ e^x dx = e^x + C. Additionally, students learn about integration by substitution and integration by parts. Understanding these fundamental formulas is essential for solving various problems in calculus.
What is the integral of the sine of x with respect to x?
∫ sin(x) dx = -cos(x) + CC is the constant of integration.
