Wherever there is an x substitute -2 and calculate the resulting sum:
f(x) = 3x² - x
→ f(-2) = 3 × (-2)² - (-2)
= 3 × 4 + 2
= 12 + 2
= 14
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if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)