if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
3x2 - 10x - 8 = (3x + 2) (x - 4)
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide
72
1 mole F2 = 37.996g F2 = 6.022 x 1023 molecules F2 85g F2 x 6.022 x 1023 molecules F2/37.996g F2 = 1.3 x 1024 molecules F2
It is not an equation it is an expression but if it was in the form of 4-x-3x2 = 0 then 3x2 by itself:- 3x2 = 4 -x
if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
By multiplying them. 4 x 6 = 24
3x3 - x2 - x - 1 = 3x3 - 3x2 + 2x2 - 2x + x - 1 = 3x2(x - 1) + 2x(x - 1) + 1(x - 1) = (3x2 + 2x + 1)(x - 1) So 3x3 - x2 - x - 1 /(x - 1) = (3x2 + 2x + 1)
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
3x2 - 7x + 2 = 3x2 - 6x - x + 2 = 3x(x - 2) - 1(x - 2) = (3x - 1)(x - 2) So x = 1/3 or x = 2
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)