You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero:
y = -3x2 + 12x - 5
y' = -6x + 12
0 = -6x + 12
6x = 12
x = 2
Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate:
y = -3x2 + 12x - 5
y = -3(2)2 + 12(2) + 5
y = -12 + 24 + 5
y = 17
So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
nice attempt :) at least you couldve said some stupid crips rolling in 6 fo's with dicks or something, which ive herd before the answer is -6 -apex-
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
The vertex is at (-1,0).
The vertex has a minimum value of (-4, -11)
The equation is linear and so has no vertex.
The vertex is at the point (0, 4).
-2-5
y = x +1 is the equation of a straight line and so has no vertex.
(3, -21)
The vertex of the positive parabola turns at point (-2, -11)
x = -3y = -14
(-3, -5)
well one foot is 12 inches, so 12x5=60, plus 6 equals 66 66 inches
It is a parabola with its vertex at the origin and the arms going upwards.