If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
y = -x2 + 1 This function describes a parabola that opens downward. To find the top of it's range, you need to find it's focal point. You can do that very easily by taking the derivative of the equation and solving it for 0: y = -x2 + 1 ∴ y' = -2x let y' = 0: 0 = -2x ∴ x = 0 Now you can calculate the y value at that point: y = -02 + 1 ∴ y = 1 So that function describes an upside down parabola whose peak is at the point {0, 1}. It's range then is: {y | y ∈ ℜ, y ≤ 1}
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
The [ 2x + 1 ] represents a function of 'y' .
0 because y=1 can be written as y = (0)x +1 and its gradient is 0.
Y = 2.5X ( + 0 ) So, zero is the Y intercept of this function.
Yes, none of the X values repeat, therefore it is a function. X=0 is not a function though.
5x²=0 X=0 the function y=5x² only intercepts x when x = 0
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
y = 8 - 2*x
(0,a)
For y - 2y - 3y equals 0, y equals 0.
equals(x,y)=1 if x=y =0 otherwise show that this function is primitive recursive
yes according to the vertical line test, it is a function because every x value has only one y output value.
a = 3 and y = 0
Assuming that b > 0, it is an inverse power function or an inverse exponential function.