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Show that sin x equals cos x for some angle t between 0 and 90?
Wiki User
∙ 14y ago
sin(x) = cos(x)
sin(x)/cos(x) = tan(x) = 1
x = arctan(1) = 45 degrees
sin(45)=cos(45) = Sqrt(2)/2 Answer: By observation. Since Sine = Opposite over hypotenuse and Cosine = Adjacent over hypotenuse. Any right angle triangle where the opposite and adjacent sides are the same length will have Sine equal to Cosine. This only happens with an isosceles triangle (two sides are equal in length). When one angle is 90o the other two are 45o.
Wiki User
∙ 14y ago
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