2x2 = 4 , Four . 2x2 = 4 , Four .
Yes, because 2x2 equals 4 and 4/2 equal 2
What is the solution set of 2x2 + x = 15
If: 2x2 = 4 Then: x = the square root of 2
First you should combine equal terms. For example, 2x2 and -4x2 can be combined as -2x2. Then you can use the quadratic formula.Additonal Answer:-2x2+5x+3-4x2+22 = 0Collect like terms: -2x2+5x+25 = 0Divide al terms by -1: 2x2-5x-25 = 0Factorise: (2x+5)(x-5) = 0Solutions are: x = -5/2 or x = 5
2x2 equals 5
2x2 = 4 , Four . 2x2 = 4 , Four .
2x2 + 11x + 15 = (x + 3)(2x + 5).
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
2x2 + 3x - 20 = (x + 4)(2x - 5).
1x100/2x2/2x2/2x2/2x2/2x2/2x2/2x2/2+50 + -50 +50=100
y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.
x = (-1 ± √11) / 2
-2x^2 = -50 x^2 = 25 x = 5, -5
no