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How would you find x when 0 equals 2sinxcosx-cosx?
2sinxcosx-cosx=0 Factored : cosx(2sinx-1)=0 2 solutions: cosx=0 or sinx=.5 For cosx=0, x=90 or 270 degrees For sinx=.5, x=30 degrees x = {30, 90, 270}
Cos x plus sin x equals 0?
cosx + sinx = 0 when sinx = -cosx. By dividing both sides by cosx you get: sinx/cosx = -1 tanx = -1 The values where tanx = -1 are 3pi/4, 7pi/4, etc. Those are equivalent to 135 degrees, 315 degrees, etc.
How do you describe how to translate the graph y equals radical x to obtain the graph of each function?
You can move it up or down by adding a constant, call it c. Let c>0 Y=radical(x)+c move it up c and y= radical(x)-c moves it down c. You can move it to the right by subtracting c inside the radical sign. Let c>0 y=radical (x-c) moves it to the right c units. y=radical (x+c) moves it to the left c units.
What is the radical equation 4 equals x2-2-x?
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
Why does sec 0 equals 1?
Secant is 1 over cosine and cosine 0 equals 1.
