y=1/sinx
y'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)
y'=(sinx*0-1(cosx))/(sin2x)
y'=(-cosx)/(sin2x)
y'=-(cosx/sinx)*(1/sinx)
y'=-cotx*cscx
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The derivative of sin(x) is cos(x).
The derivative of x divided by 3 is 1/3. This can be found using the power rule of differentiation, where the derivative of x^n is nx^(n-1). In this case, x can be written as x^1, so the derivative is 1(1/3)*x^(1-1) = 1/3.
(1/2(x^-1/2))/x
Well if you have 5/X then you can rewrite this like 5x-1. And the derivative to that is -5x-2 and that can be rewrote to: -(5/x2).
at the angles 0 and 360 degrees, or 0 and 2pi