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Work of 1 Joules is done in stretching a spring from its natural length to 12 cm beyond its natural length what is the force in Newtons that holds the spring stretched at the same distance 12 cm?
First, set up the integral W= /int_{0}^{0.12}k*x. Solve the integral on the right side. It should lead to W= (9/1250)*k. Substitute W=1 on the left side and solve for k. k should equal (1250/9) Substitute k=(1250/9) and x=0.12 in the equation F=kx and solve for F. F should equal (50/3).
Jane is 2 mi offshore in a boat and wishes to reach a coastal village 6 miles down a straight shoreline from the point nearest the boat She can row 2 mph and can walk 4 mph Where should she land her?
r = distance she rowedw = distance she walkedt = total time to reach villaget = r/2 + w/5r^2 = 2^2 + (6 - w)^2r = (4 + 36 - 12w + w^2)^(1/2)r = (w^2 - 12w + 40)^(1/2)t = (w^2 - 12w + 40)^(1/2)/2 + w/5t' = (1/2)(1/2)(w^2 - 12w + 40)^(-1/2)(2w - 12) + 1/5 = 0(1/2)(1/2)(w^2 - 12w + 40)^(-1/2)(2w - 12) = -1/5(1/2)(w - 6) = -1/5(w^2 - 12w + 40)^(1/2)5(w - 6) = -2(w^2 - 12w + 40)^(1/2)25(w^2 - 12w + 36) = 4(w^2 - 12w + 40)(25 - 4)w^2 + (-25*12 + 4*12)w + 25*36 - 4*40 = 021w^2 - 252w + 740 = 0w = 6.87, 5.13 midiscard 6.87 ( > 6)r = (w^2 - 12w + 40)^(1/2)r = 2.18 miShe should land her boat 5.13 miles away from village
Can anyone find a formula for the described function A rectangle has a perimeter of 20m Express the area of the rectangle as a function of the length of one of its sides?
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
What are domain and range of function graph below?
Type your answer here... C.H(w) > 0
How many calories does it take to raise 1 kg 1 meter?
The work done is transformed into potential energy (in the object lifted) so W = m x g x dz where W = Work m = mass g = acceleration due to gravity dz = change in height => W = 1kg x 1m x 9.81m/s/s => W = 9.81J 1J = 0.239 calories => It takes 2.345 calories to lift 1kg by 1m NOTE These are "real" calories. The calories usually talked about in relation to dieting etc are kilo-calories so to equate this value to the calories in a chocolate bar, divide by 1000
Evaluate t-7over w for t equals -3 and w equals -2?
To evaluate t-7 over w for t equals -3 and w equals -2, we substitute -3 for t and -2 for w in the expression. This gives us (-3) - 7 over (-2), which simplifies to -10 over -2. Further simplifying, we get 5 as the final result.
What is the answer to this equation solve the equation w equals 2 pi StartRoot StartFraction x Over t EndFraction EndRoot for the variable x Assume all other letters represent nonzero constants?
w=2*pi*sqr(x/t) First divide each side by 2*pi w/(2pi)=sqr(x/t) Next square both sides (w/2pi)^2=x/t Next multiply both sides by t t(w/2pi)^2=x
Can you help solve the equation w equals 3 pi StartRoot StartFraction x Over t EndFraction EndRoot for the variable x Assume all other letters represent nonzero constants?
w=3pi*sqr(x/t) First divide each side by 3pi w/3pi=sqr(x/t) Next square both sides. (w/3pi)^2=x/t Next multiply both sides by t t(w/3pi)^2=x
If length l and width w then solve for this equation 5 divded by w equals 1.61803?
1.61803.... == solve for w. thanks, sherri
Assuming cos t equals 45 and cos w equals 89 both t and w are positive and both t and w determine a terminal point in quadrant 1 then what best describes the relations?
t> w
Solve the equation of w - 4 equals -2?
6
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
22
Solve for H.. A equals L x W x H?
H = A/(L x W)
What is W equals P half minus L solve for L?
L = P/2 - W.
How do you solve 1-w equals 0.95?
0.050000000000000044
Can you solve 4w plus negative 9 equals 272?
w = 70.25
4 over 9 w equals negative 8?
The answer to the problem of 4 over 9w equals negative 8 is w equals -18.
