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If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
How do you solve 40 equals 4-6x?
40=4-6x 40-(4)=4-6x-(4) 36=-6x -6=x
What times 40 equals 8000?
To find the value that, when multiplied by 40, equals 8000, you can set up an equation: 40x = 8000. To solve for x, you divide both sides by 40: x = 8000 / 40. Therefore, x = 200. So, 200 times 40 equals 8000.
Solve the following 32 divided by 4 plus 4 x 8 equals?
The final answer is 40.
40 times something equals 1600?
Well, darling, if you want to solve that little math problem, all you have to do is divide 1600 by 40. And voila, you'll find out that something is equal to 40. But hey, I'm not here to do all the work for you, so grab a calculator and get cracking!
If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
What is the area if perimeter is 96 and l equals 5w?
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
The perimeter of a rectangular playing field is 244 feet If its length is 2 feet longer than twice its width what are the dimensions of the field?
The answer is W=40 and L=82 If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width. P=2L+2W L=2W+2 244=2(2W+2)+2W 244=4W+4+2W 244=6W+4 6W=244 244/6W= W=40 Now plug the 40 in for w in: L=2W+2 L=2(40)+2 L=80+2 L=82 final answer: L=82 and W=40
What is the perimeter of a garden 20 ft long and 15 ft wide?
2L + 2W 2*20=40 2*15=30 40+30= 70 ft
What is the length and width of a rectangular garden that's perimeter is 40 feet and the width is 2 more than one half the length?
2L+2W=40, W=2+L/2, so 2L+4+L=40, 3L=36, L=12, W=8.
What is the dimensions of rectangle room is 8ft longer than twice the width the perimeter is 136?
P = 2l + 2wl = 2w + 8P = 136136 = 2l + 2w136 = 2(2w+8) + 2w136 = 4w + 16 + 2w136 = 6w + 16120 = 6ww = 20l = 2(20) + 8l = 40 + 8l = 48CHECK:136 = 2l + 2w136 = 2(48) + 2(20)136 = 96 + 40136 = 136
20h-40 equals 8h plus 152?
How do you solve this equation 20h-40=8h+152 ?
Solve the proportion 3 over 8 equals x over 40?
Is it 15 over 40?
What is w and l in lw equals 2800 and 2l plus 2w equals 220?
l + w = 110 so l = 110 - w, making lw = 110w - w2 which equals 2800. This rearranges to w2 - 110w + 2800 = 0. The factors of this are (w - 70)(w - 40) so w = 40 and l = 70. Factors of 2800 are 2 x 1400, 4 x 700, 5 x 560, 7 x 400, 8 x 350, 10 x 280, 20 x 140, 25 x 112, 70 x 40
EO equals 2X minus 20 and OC equals 70 minus X solve for X?
40
How do you solve 40-7x equals -16?
40 -7x = -16 -7x = -16 -40 -7x = -56 x = 8
What is the answer to -40 equals -5p?
-35
