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The curve y ax2 bx c passes through the point 1 2 and is tangent to the line y x at the origin Find ab and c?
Sathishgajarla
y = ab^2+bx+c at point (1,2)
y' = x
since y' is also known as the slope, write the equation of point (1,2) at slope = X
y- 2 = x (x-1)
y= x^2-x+2
a=1
b=-1
c=2
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