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f'(1) is the slope of the tangent line of the curve at x=1. Because the tangent line at x=1 goes through (1,7) and (-2,-2), its slope is (7-(-2))/(1-(-2))=9/3=3. So f'(1)=3.

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Q: If the line tangent to the graph of the function f at the point 1 7 passes through the point -2 -2 then f prime of 1 is?
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