The slope of any line is rise/run, or change in y divided by change in x.
On a distance-time curve, time is the variable on the x axis, and distance is the variable on the y axis. This means that when a tangent is drawn at any point on the curve, its slope becomes change in distance divided by change in time, for example, m/s, km/h, etc. These units align with the units for velocity, and therefore the slope of the tangent line on a distance-time curve is the velocity.
velocity.
The rate of Change in acceleration.
The instantaneous slope of a curve is the slope of that curve at a single point. In calculus, this is called the derivative. It also might be called the line tangent to the curve at a point. If you imagine an arbitrary curve (just any curve) with two points on it (point P and point Q), the slope between P and Q is the slope of the line connecting those two points. This is called a secant line. If you keep P where it is and slide Q closer and closer to P along the curve, the secant line will change slope as it gets smaller and smaller. When Q gets extremely close to P (so that there is an infinitesimal space between P and Q), then the slope of the secant line approximates the slope at P. When we take the limit of that tiny distance as it approaches zero (meaning we make the space disappear) we get the slope of the curve at P. This is the instantaneous slope or the derivative of the curve at P. Mathematically, we say that the slope at P = limh→0 [f(x+h) - f(x)]÷h = df/dx, where h is the distance between P and Q, f(x) is the position of P, f(x+h) is the position of Q, and df/dx is the derivative of the curve with respect to x. The formula above is a specific case where the derivative is in terms of x and we're dealing with two dimensions. In physics, the instantaneous slope (derivative) of a position function is velocity, the derivative of velocity is acceleration, and the derivative of acceleration is jerk.
When you take the derivative of a function, you are seeking a variation of that function that provides you with the slope of the tangent (instantaneous slope) at any value of (x). For example, the derivative of the function f(x)=x^2 is f'(x)=2x. Notice that the derivative is denoted by the apostrophe inside the f and (x). Also note that at x=0, f'(x)=0, which means that at x=0 the slope of the tangent is zero, which is correct for the function y=x^2.
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.
Tangent of the slope at any point = velocity
yes, the slope of the line is the tangent of the angle
No, it is instantaneous acceleration.
It will measure acceleration in the direction towards or away from the origin.
instantaneous
Take a tangent at the point where you want the slope. Then the slope of the graph at that point is the slope of the tangent, which is found by taking another point on the tangent and then taking the change in y between the two points and divid it by the change in x.
The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.
The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.
it measures the magnitude of acceleration, but it can't tell you the direction of the acceleration.
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
The slope of a line and the tangent of the angle between the positive x-axis and the line are related because the tangent of the angle is defined as the ratio of the y-coordinate and the x-coordinate of some point on the line.