The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
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x2+5x+6 = (x+2)(x+3)
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
6 + 2x = 5x + 9 , 6 - 9 = 5x - 2x , -3 = 3x , x = -1
Watch closely:5x - 6y = 13Subtract 5x from each side of the equation:-6y = 13 - 5xDivide each side by -6 :y = 5x/6 - 13/6
5x+10=40 5x+10-10=40-10 5x=30 5x/5=30/5 x=6