x2+5x+6 = (x+2)(x+3)
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
x2 - 36 = x2 - 62 = (x + 6)(x - 6)
6 + 2x = 5x + 9 , 6 - 9 = 5x - 2x , -3 = 3x , x = -1
Watch closely:5x - 6y = 13Subtract 5x from each side of the equation:-6y = 13 - 5xDivide each side by -6 :y = 5x/6 - 13/6
x2 + 5x =6 x2+5x -6 = 0 (x+6)(x-1) = 0 x+ 6 = 0 x = -6 x-1 = 0 x = 1
x2 + 5x = 6Subtract 6 from both sides:x2 + 5x - 6 = 0Factor:(x + 6)(x - 1) = 0The first value:x + 6 = 0, so x = -6The second value: x - 1 = 0, so x = 1The possible values of x are -6 and 1.
x2 - 5x + 6 = (x - 2)(x - 3)
x2 + 5x + 6 = (x + 2)(x + 3)
(x - 2)(x - 3)
x2+5x-6 = (x+6)(x-1) when factored
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x+6 = (x+2)(x+3)
x2-5x-66 x2-11x+6x-66 x(x-11)+6(x-11) (x+6)(x-11)
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6