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The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
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Which of the binomials below is a factor of this trinomial x2 plus 5x plus 6?
x2+5x+6 = (x+2)(x+3)
What is 2x cubed plus x squared minus 13x plus 6 divided by x minus 2 giving reasons why your answer is correct?
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
What is x2 minus 36 factorised?
x2 - 36 = x2 - 62 = (x + 6)(x - 6)
What is 6 plus 2x equals 5x plus 9?
6 + 2x = 5x + 9 , 6 - 9 = 5x - 2x , -3 = 3x , x = -1
How do you solve for y in 5x-6y equals 13?
Watch closely:5x - 6y = 13Subtract 5x from each side of the equation:-6y = 13 - 5xDivide each side by -6 :y = 5x/6 - 13/6
What are the possible values for x if x squared plus 5x equals 6?
x2 + 5x =6 x2+5x -6 = 0 (x+6)(x-1) = 0 x+ 6 = 0 x = -6 x-1 = 0 x = 1
What are the possible values for x if x to 2nd power plus 5x equals 6?
x2 + 5x = 6Subtract 6 from both sides:x2 + 5x - 6 = 0Factor:(x + 6)(x - 1) = 0The first value:x + 6 = 0, so x = -6The second value: x - 1 = 0, so x = 1The possible values of x are -6 and 1.
What are the factors of x2 - 5x plus 6?
x2 - 5x + 6 = (x - 2)(x - 3)
What is x2 plus 5x plus 6 factored out?
x2 + 5x + 6 = (x + 2)(x + 3)
What is the factor of x2 - 5x - 6?
(x - 2)(x - 3)
How do you factor x2 plus 5X-6 into two binomials?
x2+5x-6 = (x+6)(x-1) when factored
Factor x2 equals -5x-6?
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
What is x2 plus 5x-6 in factoring?
x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)
X2 plus 5x plus 3 equals 9?
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
Which of the binomials below is a factor of this trinomial x2 plus 5x plus 6?
x2+5x+6 = (x+2)(x+3)
What is the factor of x2-5x-66?
x2-5x-66 x2-11x+6x-66 x(x-11)+6(x-11) (x+6)(x-11)
X2 plus 5x plus 6 how to solve?
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
