Provided that x- 2 is not zero:
2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6
= 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2)
= (x - 2)*(2x2 + 5x - 3)
Therefore,
(2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3
If x = 2 so that x - 2 = 0, then the expression is not defined.
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The answer to this depends on what you mean by "x 7" If you mean: x2 -7x, then it can be factored out as x(x - 7) If you mean: x2 - x7, then you can factor it out as: x2(1 - x5) If you mean: x2 - x + 7, then it can not be factored If you mean: (x2 - x)7, then the inner term can be factored, giving you (x[x - 1])7 If you mean something else, then you will need to be more clear with your question.
Undefined: You cannot divide by zero
The noun 'pleasure' is the subject of the sentence.
Find dy/dx of y=1/x. It may be simpler for you to examine the equation y=x^-1. This equation is the exact same as y=1/x. Therefore just multiply -1 by x and subtract 1 from the exponent giving you -x^-2 or y=-(1/x^2). You can also do it through quotient rules. Therefore take the derivative of the top 1 which = 0 and multiply that by the bottom X which will give you 0. Then subtract the derivative of the bottom x this equals 1 and multiply it by the top (1). Put this all over the bottom squared. Which leads to -1/x^2. y=1/x = y=x^-1 = -x^-2 = -(1/x^2)=dy/dx or y=1/x = ((0*x)-(1*1)/x^2 = dy/dx=-1/x^2
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