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Q: What function would have the point 0 0 on it's graph?
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Is the graph of a quadratic function contains the point 0 0?

Some do and some don't. It's possible but not necessary.


What are domain and range of function graph below?

Type your answer here... C.H(w) > 0


What is concavity of a function?

Just as the slope of the tangent line to the graph of f at the point (x, f(x)) describes the behavior of the function, concavity describes the behavior of the slope. As x increases (graph goes from left to right), one of the following is true:Concavity is positive, so the slope slowly increases.Concavity is negative, so the slope slowly decreases.Concavity is equal to zero, so the slope is constant.Again, remember that concavity directly affects the slope, NOT the function itself. I mean this in the sense that concavity affects slope affects function.Mathematically speaking, you can find the concavity at a certain point by taking the derivative of the derivative of the function (accurately called the second derivative, f''). So, when you take the derivative of a function, you get the first derivative, f' (describing slope), and the derivative of that is the second derivative (describing the concavity).Last but not least, here is a handy way to find the concavity of a function by looking at its graph:Concavity is positive when the graph turns up, like a smiling emoticon (look at a graph of f(x) = x2 for an example).First observe that f'(x) = 2x.We see that f' < 0 when x < 0 and f' > 0 when x > 0. So that the graph is decreasing on the negative real axis and the graph is increasing on the positive real axis.Next observe that f''(x) = 2.Thus, f'' > 0 at all points. Thus the graph is concave up everywhere.Finally observe that the graph passes through the origin.Concavity is negative when the graph turns down, like a frowning emoticon (look at a graph of f(x) = -x2 for an example).First observe that f'(x) = -2x.We see that f' > 0 when x < 0 and f' < 0 when x > 0. So that the graph is increasing on the negative real axis and the graph is decreasing on the positive real axis.Next observe that f''(x) = -2.Thus, f'' < 0 at all points. Thus the graph is concave down everywhere.Finally observe that the graph passes through the origin.Look at the graph of f(x) = x3First observe that f'(x) = 3x2.Thus, f' &ge; 0 everywhere. The function is always increasing.Next observe that f''(x) = 6x.Thus, f'' < 0 when x < 0 and f'' > 0 when x > 0. So the graph is concave down on the negative real axis and concave up on the positive real axis.Finally observe that the graph passes through the origin.Concavity is zero when the graph is linear OR at a point where it stops turning up and starts turning down, and vice versa.


What is the graph of logarithm functions?

The graph of y = log(x) is defined only for x&gt;0. The graph is a monotonic increasing function over its domain. It starts from an asymptotic "minus infinity" when x approaches 0. It passes through the value y = 0 when x = 1. The graph is illustrated at the link below.


How does the graph of the cosine function differ from a graph of a sine function?

the graph of cos(x)=1 when x=0the graph of sin(x)=0 when x=0.But that only tells part of the story. The two graphs are out of sync by pi/2 radians (or 90&deg;; also referred to as 1/4 wavelength or 1/4 cycle). One cycle is 2*pi radians (the distance for the graph to get back where it started and repeat itself.The cosine graph is 'ahead' (leads) of the sine graph by 1/4 cycle. Or you can say that the sine graph lags the cosine graph by 1/4 cycle.

Related questions

Is the graph of a quadratic function contains the point 0 0?

Some do and some don't. It's possible but not necessary.


0 pi is not a point on the graph of which inverse function?

Arcsin


What is y equals 3x?

I don't understand your question but y=3x is the function of a graph, to graph the function you would plug points into the function such as x=0, x=1, x=-1 and you would find the y values at each point so that you can graph it. In this case the graph is a parabola which has a u shape.


What is 6's function?

if I'm understanding you correctly you are asking what the graph of.. f(x)=6 would look like..which would be a point at (0, 6) and a horizontal line across the graph through that point i hope that helped


What is the highest point on a graph?

The highest point on a graph is when the derivative of the graph equals 0 or the slope is constant.


What does 0 mean in a graph?

It is the point of origin of the x and y axes of the graph


What point do the axes cross in a graph?

It is at the point of origin which is at (0, 0)


If the parents function is y4x which is the function of the graph?

The function y = x is the graph that passes from the points (-1, -1), (0, 0), and (1, 1) The function y = 4x is the graph that passes form the points (-1, -4), (0, 0), and (1, 4) Sketch these graphs in a same x and y coordinate system, and you can see both of them


What is the optimum point on a graph?

The maximum. At this point the slope will be 0.


What is the point at which a graph crosses the y-axis?

This is called the y-intercept and represents the value of the plotted function at x = 0.The place where the graph crosses the y axis is called the y intercept.


What is the 0 point of a graph called?

The origin


How do you identify a function graphically?

The normal test for checking that a graph represents a function is to check that it is not one-to-many. That is, one value of x does not get mapped onto more than one value of y. If you can draw any vertical line that intersects the graph at more than one point then it is not a function. If no such line can be drawn then it may be a function. You still have no guarantee that it is.One more requirement of a function is that every point in the domain has an image in the codomain (range).Consider the graph ofy = 2x for 0 < x < 2andy = 2x for 2 < x < 4Is it a function over the domain 0 < x < 4?For every point in the domain there must be a point in the range. It is not possible to check this graphically.In this respect, the question is flawed.