Factor. X^2 + 12X X(X + 12) = 0 X = 0 ------------- X + 12 = 0 X = - 12 --------------
8
5x-8 + 7x 12x-8 12x = 8 x = 8/12 x= 2/3
y - 8 = x^2 + 12x + 36 y - 8 = (x + 6)^2 y = (x + 6)^2 + 8 or f(x) = (x + 6)^2 + 8 So -h = 6 so that h = -6, and k = 8
The factors of 5 are 1 and 5. 12 = 2 x 5 + 2 x 1, therefore: 4x2 +12x +5 = (2x + 1)(2x + 5)
(x - 8)(x - 4)
It is x^2 + 12x or x(x + 12).
4x2+12x = 4x(x+3) when factored
If: y = 4x^2 -12x -3 and y = x^2 +11x +5 Then: 4x^2 -12x -3 = x^2 +11x +5 Transposing terms: 3x^2 -23x -8 = 0 Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8 Therefore the x coordinates are: -1/3 and 8
Factor. X^2 + 12X X(X + 12) = 0 X = 0 ------------- X + 12 = 0 X = - 12 --------------
x2+12x+11=0 (x+11)(x+1)=0 x=-11 or x=-1
That will depend on the value of x
x(x + 3)(x - 4)
8
If you mean: 4x squared+12x-40 then it is (x+5)(x-2) after dividing all terms by 4
5x-8 + 7x 12x-8 12x = 8 x = 8/12 x= 2/3
(75y - 12x^2) * y = 75y^2 -12x^2y 75y - (12x^2 * y) = 75y -12x^2y