(tan x + cot x)/sec x . csc x The key to solve this question is to turn tan x, cot x, sec x, csc x into the simpler form. Remember that tan x = sin x / cos x, cot x = 1/tan x, sec x = 1/cos x, csc x = 1/sin x The solution is: [(sin x / cos x)+(cos x / sin x)] / (1/cos x . 1/sin x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (1/sin x cos x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (sin x . cos x) then sin x. sin x + cos x . cos x sin2x+cos2x =1 The answer is 1.
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
I get x*x^x-1 + lnx*x^x = x^x + x^xlnx = x^x * (1+lnx) Here, ^ is power; * = times; ln = natural logratithm ( base e)
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
24 x 3 x 17 = 816
34 x 24 = 816
816 x 7 = 5712
816 = 2 x 2 x 2 x 2 x 3 x 17
18945 is the answer
816 = 1 x 816, 2 x 408, 3 x 272, 4 x 204, 6 x 136, 8 x 102, 12 x 68, 16 x 51, 17 x 48, 24 x 34.
816 = 24 x 31 x 171
It is: 24*3*17 = 816 2^4 x 3 x 17
24 x 3 x 17
116.5714
240/816 = 2 x 2 x 2 x 2 x 3 x 5 / 2 x 2 x 2 x 2 x 3 x 17
48 x 17 = 816