x^0 = 1 for all x. The derivative of 1 is always zero.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.
The first derivative of e to the x power is e to the power of x.
x^0 = 1 for all x. The derivative of 1 is always zero.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
Oh, dude, the third derivative of ln(x) is -2/(x^3). But like, who really needs to know that, right? I mean, unless you're planning on impressing your calculus teacher or something. Just remember, math is like a puzzle, except no one actually wants to put it together.
The derivative of ex is ex
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
2x is the first derivative of x2.
the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.