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Find dy/dx of y=1/x. It may be simpler for you to examine the equation y=x^-1. This equation is the exact same as y=1/x. Therefore just multiply -1 by x and subtract 1 from the exponent giving you -x^-2 or y=-(1/x^2).
You can also do it through quotient rules. Therefore take the derivative of the top 1 which = 0 and multiply that by the bottom X which will give you 0. Then subtract the derivative of the bottom x this equals 1 and multiply it by the top (1). Put this all over the bottom squared. Which leads to -1/x^2.
y=1/x = y=x^-1 = -x^-2 = -(1/x^2)=dy/dx
or
y=1/x = ((0*x)-(1*1)/x^2 = dy/dx=-1/x^2
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What is the derivative of ln1 divided by x?
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What is the derivative of x divided by y?
You have to specify more information than that. If y is an independent variable and you're talking about the derivative with respect to x, it would be 1/y.
What is the derivative of 2lnx?
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
Derivative of x 1?
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