The answer to this depends on what you mean by "x 7"
If you mean:
x2 -7x, then it can be factored out as x(x - 7)
If you mean:
x2 - x7, then you can factor it out as: x2(1 - x5)
If you mean:
x2 - x + 7, then it can not be factored
If you mean:
(x2 - x)7, then the inner term can be factored, giving you (x[x - 1])7
If you mean something else, then you will need to be more clear with your question.
2(x - 7)(x - 1)
(x + 2)(x - 4)
x(x - 2)
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
7
x(x - 7)
What about it? Factorise it?
(x - 3)(2x - 7)
13X squared + 7X + 12
X2 - 4= (x + 2)(x - 2)===========
( x2 - 121 ) = (x + 11) times (x - 11)
3x2 - 8x = x(3x - 8)
x(x-7)
7x-x2 = x(7-x)
5x2 + 9x + 13 has no real factors.
It is (x+6)(x+7) when factored
(x+4)(x-7)