-3x + 1
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
(2x+5)(2x+5)
4x2 + 12x + 5 = (2x + 1)(2x + 5).
2x + 5 - 5 = 2x. You can not solve for x because this is not an equation.
Y = 2x-5 and Y = 2x plus 7 is a linear system which intersects at points (-2,2)
4x3+10x2+2x+5= (2x+5)(2x2+1)
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
(2x+5)(2x+5)
2x
(2x+5)(2x+1)
-2x^4+16 +2x^4+9-3x^5=-3x^5+25. There is no "answer" because there is no equation.
3x+5 = 2x+13 3x-2x = 13-5 x = 8
4x2 + 12x + 5 = (2x + 1)(2x + 5).
(2x - 5)(2x - 5) or (2x - 5) squared
I'm answering this based on the way you wrote it. If you meant something different, please substitute words where necessary. x2-2x+4+2x+1-x62+5=2x-2x+4+2x+1-62x+5=-60x+10
2x+x+5+3x-6=6x-1
X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0