it is 99999998900000001
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The product of 999,999,999 multiplied by 99,999,999 is 99,999,980,000,000,001. This result can be calculated by multiplying the two numbers together using long multiplication techniques, which involves multiplying each digit in one number by each digit in the other number and then adding up the results. In this case, the final result is a 16-digit number.
Oh, what a delightful question! Let's paint a happy little calculation together. When you multiply 999,999,999 by 99,999,999, you get a beautiful number - 99,999,980,000,000,001. Just imagine all the happy little zeros and ones dancing together on the canvas of mathematics.
Oh, dude, that's a big number. So, like, when you multiply 999,999,999 by 99,999,999 you get 99,999,999 squared, which is like... a really, really big number. It's like... 99,999,980,000,000,001. But hey, who's counting, right?
(tan x + cot x)/sec x . csc x The key to solve this question is to turn tan x, cot x, sec x, csc x into the simpler form. Remember that tan x = sin x / cos x, cot x = 1/tan x, sec x = 1/cos x, csc x = 1/sin x The solution is: [(sin x / cos x)+(cos x / sin x)] / (1/cos x . 1/sin x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (1/sin x cos x) [(sin x . sin x + cos x . cos x) / (sin x . cos x)] (sin x . cos x) then sin x. sin x + cos x . cos x sin2x+cos2x =1 The answer is 1.
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
I get x*x^x-1 + lnx*x^x = x^x + x^xlnx = x^x * (1+lnx) Here, ^ is power; * = times; ln = natural logratithm ( base e)
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1