x times x to the first power is x to the second power
x to the 5th power times y to the fourth power
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
I get x*x^x-1 + lnx*x^x = x^x + x^xlnx = x^x * (1+lnx) Here, ^ is power; * = times; ln = natural logratithm ( base e)
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
If a number is raised to the fourth power, it is multiplied by itself four times. For example, 24 = 2 x 2 x 2 x 2 = 16.
X to the fourth power is... X times X times X times X
x times x times x times x
Evaluate simply means work out. You times the first number by itself. The second number which is is small and beside the top corner of the first number decides how many times the first number gets times by itself. Here are 4 examples: 2 to the power of 4 = 2 x 2 x 2 x 2= 16 3 to the power of 3 = 3 x 3 x 3= 27 4 to the power of 3= 4 x 4 x 4= 64 5 to the power of 5 = 5 x 5 x 5 x 5 x 5= 3125
x to the 5th power times y to the fourth power
6x5
10 to the first power is 10. 6.7 x 10 = 67
x
x times x times x
pover x times 9 plus power of x times 3
y*x8
x^7
The following is not a proof or a reason, but it's a demonstrationthat might be intuitively satisfying:'X' mentioned 4 times: X times X times X times X = X to the fourth power'X' mentioned 3 times: X times X times X = X to the third power'X' mentioned 2 times: X times X = X to the second power'X' mentioned 1 time: X = X to the first powerBut this is not the question you should be asking. What you should really beworrying about is:"Why is a number to the zero power equal 1 ?" Answer:Let's use 3 as an example:33=2732=931=3