x-int. is -5 y-int. is 6
the Y in the sentence X plus Y equals 5 is Y=3 or 2 if the X is 2 or 3
at y=6.Make x==0 // then you get the y interceptthen y=0+6solve for y, y=6
-6
x-y = 6 -x-3y = 22 -4y = 28 y = -7 So by substituting: x = -1 and y = -7
you subtract x from both sides for both equations to get it in y= form. so... x+y=5 x+y-x=5-x y=5-x x+y=6 x+y-x=6-x y=6-x thanks:D but i meant with absolute value signs it was supposed to look like this : |x+y|=5 and |x|+|y|=6 ... but when i typed it in answers.com changed it
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
Two solutions:x = 5 and y = 6, orx = 6 and y = 5.
10
No.
equation1: y+1 = x => y = x-1 equation 2: y = x2-6x++5 If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6 Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5 Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5
y is increased by 6.
y + 1 = xy = x² - 6x + 5Rearrange {1} to make y the subject, substitute for y in the second and solve the quadratic:y + 1 = x → y = x - 1y = x² - 6x + 5→ x - 1 = x² - 6x + 5→ x² - 7x + 6 = 0→ (x - 1)(x - 6) = 0→ x = 1 or 6→ x = 1: y = 1 - 1 = 0& x = 6 → y = 6 - 1 = 6→ the solutions are the points (1, 0) and (6, 5)
Given: x + y = 5 2x + y = 6 We can subtract the second equation from the first to get: -x = -1 x = 1. From there, substituting back in to the first equation yields: 1 + y = 5 y = 4. The solution is (1, 4).
It is (5 and minus1).
x = -6 y = -11
If: x+2 = y+6 Then: y = x-4