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  1. y + 1 = x
  2. y = x² - 6x + 5

Rearrange {1} to make y the subject, substitute for y in the second and solve the quadratic:

y + 1 = x → y = x - 1

y = x² - 6x + 5

→ x - 1 = x² - 6x + 5

→ x² - 7x + 6 = 0

→ (x - 1)(x - 6) = 0

→ x = 1 or 6

→ x = 1: y = 1 - 1 = 0

& x = 6 → y = 6 - 1 = 6

→ the solutions are the points (1, 0) and (6, 5)

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Q: What are the solutions to the simultaneous equations of y plus 1 equals x and y equals x square -6x plus 5?
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