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It looks like it could be: 0 + 2 = 2 2 + 4 = 6 6 + 6 = 12 The next logical answers would be: 12 + 8 = 20 20 + 10 = 30 30 + 12 = 42 And so on...
Add 1 to the coefficient and divide by that term. int[f(X) by the power rule is this.......X(n + 1)/nint(6X)= 6/2(X2)= 3X2 + C--------------
you can add logarithms if they both have the same baseuse this rule if they both have the same base, a:logam+logan= loga(mxn)all you have to do is multiply the base numerals together (mxn) :)ln5+2ln6= loge(5)+2loge(6)simplify it usingnlogam= logam^n= loge(5)+loge(6)^2= loge(5)+loge(36)use the first rule at the very top= loge(5x36)=loge(180)
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If the first term is 7x^5, ∫7x^5 -cox dx is the expression. You can split this up into two integrals if that helps you visualize the terms. ∫7x^5dx - ∫cox dx. We know that the antiderivative of cosx is sinx, so that is our second term. In the first term, we must undo the power rule, adding one to the power and multiplying by the reciprocal of the power. This gives us (7/6)x^6. So, our final antiderivative expression is (7/6)x^6-sinx+C, with C being an arbitrary constant.