If the first term is 7x^5, ∫7x^5 -cox dx is the expression. You can split this up into two integrals if that helps you visualize the terms. ∫7x^5dx - ∫cox dx. We know that the antiderivative of cosx is sinx, so that is our second term. In the first term, we must undo the power rule, adding one to the power and multiplying by the reciprocal of the power. This gives us (7/6)x^6. So, our final antiderivative expression is
(7/6)x^6-sinx+C, with C being an arbitrary constant.
Chat with our AI personalities
-e-x + C.
You can't, unless it's an initial value problem. If f(x) is an antiderivative to g(x), then so is f(x) + c, for any c at all.
If f' (x) = x43, then f(x) = (1/44) x44 + C.
One can use integration by parts to solve this. The answer is (x-1)e^x.
-1