First of all, the word "equals" doesn't belong in an "inequality".
Let's assume you actually meant to call it an "equation".
Now, we have the nagging felling that you're not exactly sure what you mean by "answer",
so we'll tell you: It means a pair of numbers that you can put in the places of 'x' and 'y'
that make the whole equation a true statement.
For example:
Can 'x' be 1 and 'y' be zero ?
If they are, you'd have 4(1) + 2(0) = 40. Is that a true statement ?
Well, it says that 4 = 40, which is a big fat lie, so 'x' can't be 1 when 'y' is zero.
Can 'x' be zero and 'y' be 20 ?
If they are, then you have 4(0) + 2(20) = 40. Is that a true statement?
Well, it says that 40 = 40, which is true, so 'x' can be zero when 'y' is 20,
and that's a good 'answer'..
But wait. You're not done. We want you to try another one:
Can 'x' be 5 and 'y' be 10 ?
If they are, then you have 4(5) + 2(10) = 40. Is that a true statement ?
Well, it says that 20 + 20 = 40, and that's true, so 'x' can be 5 when 'y' is 10.
That's another good answer.
How many answers can this thing have ? We're sure that if you're still reading,
you're about to be surprised.
Your equation ... [ 4x + 2y = 40 ] ... is the equation of a straight line.
Every point on the line is an 'answer' to the equation.
How many points are there on a line ? An infinite number of them.
Your equation has an infinite number of correct 'answers'.
And also an infinite number of wrong answers ... all of the points that aren't on the line.
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
x = 2, and y = 0. Here's one way to solve:Multiply the second equation (both sides) by 3, then add the two equations:8x + 6y = 1612x - 6y = 24----------20x = 40 ----> x = 2, then substitute x=2 into one of the original equations:8*2 + 6y = 16 --> 6y = 0, and y=0. Check with the other equation: 4*2 - 2y = 8 ---> -2y = 0, and y = 0.
5x+10=40 5x+10-10=40-10 5x=30 5x/5=30/5 x=6
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
5x+32+7x+8=180. By the laws of commutativity we can thus say that 12x+40=180. Subtracting 40 we get 12x=140. Divide by 12 and you get x=(do it yourself) This has nothing to do with calculus by the way.
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
2y-5=11y+40 Subtract 2y from both sides -5=9y+40 Subtract 40 from both sides. -45=9y Divide by 9. -5=y
y=16 x= -4
Add the two equations you get 5y = 60 so y = 12 and x = 2
They are all the points on or above the line [ y = -2x + 20 ]. There are a lot of them.
6y-2y=40 6-2=40/y 4=40/y y=10 6(10)-2(10)=40
120
10y plus 40 equals 50y.
Nothing will solve an expression. You need an equation (an equality or an inequality) beofre a solution of any kind is possible. Tha means you need something on both sides of the equality (or inequality) sign.
280
If 40 plus x equals 25 then x is equal to -15.
this equals 818