Generally, the derivative of sine is cosine.
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2.5x2 + any constant
-cos(x)
When you solve for the 2nd derivative, you are determining whether the function is concave up/down. If you calculated that the 2nd derivative is negative, the function is concave down, which means you have a relative/absolute maximum, given that the 1st derivative equals 0. To understand why this is, think about the definition of the 2nd derivative. It is a measure of the rate of change of the gradient. At a maximum, the gradient starts positive, becomes 0 at the maximum itself and then becomes negative, so it is decreasing. If the gradient is going down, then its rate of change, the 2nd derivative, must be negative.
The derivative of negative cosine is positive sine.
y = Sin(pi) = 0 Then its derivative is dy/dx = Cos(pi). = -1
Generally, the derivative of sine is cosine.
∫ -cos(x) dx = -sin(x) + C
-(1/2)X^2 [negative half X squared]
negative cotangent -- dcot(x)/dx=-csc^2(x)
The derivative of sin (x) is cos (x). It does not work the other way around, though. The derivative of cos (x) is -sin (x).
Yes: cosecant = 1/sine If sine negative, 1/sine is negative → cosecant is negative.
The deriviative of sine(x) is cosine(x).
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An integral and an anti-derivative are the same thing. Integration means the process of finding the integral, just as anti-differentiation means the process of finding the anti-derivative.
The negative sine graph and the positive sine graph have opposite signs: when one is negative, the other is positive - by exactly the same amount. The sine function is said to be an odd function. The two graphs for cosine are the same. The cosine function is said to be even.