Sine (pi) is a constant, so the derivative of sine (pi) is zero.
The anti-derivative of any constant c, is just c*x. Thus, the antiderivative of pi is pi*x. We can verify this by taking the derivative of pi*x, which gives us pi.
The derivative of sin (x) is cos (x). It does not work the other way around, though. The derivative of cos (x) is -sin (x).
d/dx[cos(pi)] = - sin(pi)
The sine of (3\pi) is 0. This is because (3\pi) corresponds to a point on the unit circle where the angle is a multiple of (2\pi) (specifically, (3\pi = 2\pi + \pi)), and the sine of any integer multiple of (2\pi) is always 0. Thus, (\sin(3\pi) = 0).
One. Exactly one.
The anti derivative of negative sine is cosine.
Generally, the derivative of sine is cosine.
The derivative of negative cosine is positive sine.
The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
The word sine, not sinx is the trigonometric function of an angle. The answer to the math question what is the four series for x sine from -pi to pi, the answer is 24.3621.
The anti-derivative of any constant c, is just c*x. Thus, the antiderivative of pi is pi*x. We can verify this by taking the derivative of pi*x, which gives us pi.
The derivative of sin (x) is cos (x). It does not work the other way around, though. The derivative of cos (x) is -sin (x).
d/dx[cos(pi)] = - sin(pi)
"Pi divided by 2" is a number, i.e. a constant. The derivative is the rate of change. The derivative of any constant is zero, because a constant never changes.
The sine of (3\pi) is 0. This is because (3\pi) corresponds to a point on the unit circle where the angle is a multiple of (2\pi) (specifically, (3\pi = 2\pi + \pi)), and the sine of any integer multiple of (2\pi) is always 0. Thus, (\sin(3\pi) = 0).
The deriviative of sine(x) is cosine(x).
y=x^pid/dx=pi*(x^pi-1)This is true because of power rule.d/dx (x^a)=a(x^(a-1))