The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
x over x is one, so the problem would be 1-2-3/2=-5/3
negative infiniti to positive infiniti
-2, 3
The graph of y = log(x) is defined only for x>0. The graph is a monotonic increasing function over its domain. It starts from an asymptotic "minus infinity" when x approaches 0. It passes through the value y = 0 when x = 1. The graph is illustrated at the link below.
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
For this question, the domain can be anything, as long as the denominator is not 0. If your question was (3x+1)/(x2-2x), the domain is all real numbers except for 0, 2. If your question was [(3x+1)/x2] - 2x, then x is not equal to zero.
All real number excluding x = 8
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
It can do. Depends on the value of x.
f(x)=(x/|x-3|)+1; domain is all real numbers except 3. f(x)=(x/(|x-3|+1)); domain is all real numbers.
-1 is the answer. With an odd number of -1s, we end up back where we started as each multiplication only switches from positive to negative.
x over x is one, so the problem would be 1-2-3/2=-5/3
negative infiniti to positive infiniti
-2, 3
The least common denominator is 24x. If all of that equals zero, x = 3/20