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6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant

6x2 -6x-16 which is 2(3x2 -2x-8)

The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also.

So we cannot factor (3x2 -2x-8) over the integers and we call it prime.

The final answer is 2(3x2 -2x-8)

Q: How do you factor 6x - 6x -16?

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(x + 2)(x - 8)

3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms

y=6x-16 y=-2x+8

6x - 2 = 16 : 6x = 16 + 2 = 18 : x = 18÷ 6 = 3 :x - 3 = 3 - 3 = 0 : x - 3 = 0

6x-14x+16=27+11 answer: 4

Related questions

x2 - 6x - 16 = (x + 2)(x - 8)

x^2+6x-16 (x+2)+(6x-16) x+8+x-16 (x+8)(x-2) here you go :)

16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)

-((x + 2)(x - 8))

-10 = 6x - 16, or 16 - 10 = 6x, or x = 1.

(x + 2)(x - 8)

6x(3x2 - x + 4)

If you mean: 8x2-56x-64 which becomes x2-7x-8 and is (x-8)(x+1) when factored

(6x+5)(6x-5)

4

The greatest common factor of 12xy2 + 6x is 6x. The greatest common factor of 12 and 6 is 6, and the greatest common factor of xy2 and x is x. If you took 6x out of both factors, the end result would be 2y2+1

x2 + 6x - 2 can not be factored