16
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
y varies as 1/x^(2) y = k X 1/^(2) y = k/x^(2) k = y x^(2) When y = 4 & x = 3 Then k = 4(3^(2)) k = 4(9) k = 36 (The constant of proportionality Hence the general equation is y = 36/x^(2) When x = 2 y = 36/2^(2) y = 36 /4 y = 9 The answer!!!!!
If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
8-4k = 40 (4k-8) - 8 = 40-8 4k = 32 4k/4 = 32/4 k =8
As x ∝ yz2 then x = kyz2 where k is a constant. Substituting the given figures, 40 = k*20*22 = 80k Then k = ½ and the formula is, x = ½yz2 So, x = ½ * 30 *32 = 135
k * 4 = 48 k = 48/4 k = 12 so 12 * 4 = 48
12 - 4 + k = 85 8 + k = 85 k = 77
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
The answer to negative 6 over 5K equals 12 is k equals -10.
k = 2 and 2 < 12
k = f(n) = 7n
k = -1
Take 3k from both sides to get k-3 equals 4, so k is 7
You have:A = K / B^3The given data gives value for K :K = ( A ) ( B )^3K = ( 28.5 ) ( - 4 )^3 = - 1824A = ( - 1824 ) / B^3Answer : A = ( - 1824 ) / ( B )^3 = ( -1824 ) ( B )^( -3 )
12
50
neg(-k) + neg(-k) = k + k = 2k = 4