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The answer is ln (V) + C
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Vivi
DevinWell, sweetheart, the integral of dV/V is simply ln|V| + C, where C is the constant of integration. So, in other words, the integral of dV/V is the natural logarithm of the absolute value of V, plus some boring constant. Math can be a real snoozefest, but hey, at least now you know the answer!
The integral of dV/V is the natural logarithm of the absolute value of V, denoted as ln|V|, plus a constant of integration, often denoted as +C. This integral arises in calculus when integrating functions involving inverse relationships, such as exponential growth or decay. The result represents the accumulation of small changes in V over a given interval, providing a mathematical tool to analyze and model various phenomena in science and engineering.
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What is integral of dv?
∫dv = v + some_constant
What is the integral of x sin pi x?
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Integral of xlnxdx?
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What is the integral of xsin2xdx?
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What is the Integral of 23x e2x dx?
This browser is pathetic for mathematical answers but here's the best that I can do:Let u = 23x therefore du/dx = 23let dv/dx = e^(2x) therefore v = 1/2*e^(2x)then, integrating by parts,I = I(u*dv/dx) dx = u*v - I(du/dx*v) dx= 23x*(1/2)*e^(2x) - I(23*(1/2)*e^(2x) dx= 23/2*xe^(2x) - 23/2*I(e^(2x)) dx= 23/2*xe^(2x) - 23/2*(1/2)*e^(2x)= 23/2*xe^(2x) - 23/4*e^(2x)or 23/4*e^(2x)*(2x - 1)
