What is the Integral of 23x e2x dx?

Answer 1

This browser is pathetic for mathematical answers but here's the best that I can do:

Let u = 23x therefore du/dx = 23let dv/dx = e^(2x) therefore v = 1/2*e^(2x)

then, integrating by parts,

I = I(u*dv/dx) dx = u*v - I(du/dx*v) dx

= 23x*(1/2)*e^(2x) - I(23*(1/2)*e^(2x) dx

= 23/2*xe^(2x) - 23/2*I(e^(2x)) dx

= 23/2*xe^(2x) - 23/2*(1/2)*e^(2x)

= 23/2*xe^(2x) - 23/4*e^(2x)

or 23/4*e^(2x)*(2x - 1)