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pendulum length (L)=1.8081061073513foot
pendulum length (L)=0.55111074152067meter
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A light is hung 15 feet above a straight horizontal path If a man 6 feet tall is walking away from the light at the rate of 5 feet per second how fast is his shadow lenghtening?
Suppose the distance from the light to the man at time t is x(t), and that the length of his shadow is s(t).By similar triangles, (x + s)/s = 15/6 = 5/2That is, x/s + 1 = 5/2 so that x/s = 3/2and therefore, s = 2x/3Then since dx/dt = 5 feet/sec, ds/dt = 2/3*5 ft/sec = 10/3 ft/sec or 3.33... (recurring) ft/sec
How Laplace Transform is used solve transient functions in circuit analysis?
f(t)dt and when f(t)=1=1/s or f(t)=k=k/s. finaly can be solve:Laplace transform t domain and s domain L.
Y' equals x plus y Explicit solution?
using Laplace transform, we have: sY(s) = Y(s) + 1/(s2) ---> (s-1)Y(s) = 1/(s2), and Y(s) = 1/[(s2)(s-1)]From the Laplace table, this is ex - x -1, which satisfies the original differential eq.derivative of [ex - x -1] = ex -1; so, ex - 1 = ex - x - 1 + xto account for initial conditions, we need to multiply the ex term by a constant CSo y = C*ex - x - 1, and y' = C*ex - 1, with the constant C, to be determined from the initial conditions.
If the discriminant is positive the equation has solution s?
two real
Is this 7x2-5x plus 2 a monomial binomial or trinomial?
The term with the highest power(s) of the unknown variable(s) is 7x2. The power is 2 so the expression is a binomial.
What is the length of a pendulum with a period of 1.20 s?
The pendulum's length is 0.36 meters or 1.18 feet.
A pendulum swings back and forth with a period of 0.5 s What is the length of the pendulum arm?
The pendulum has an arm length of 0.06 meters or 2.36 inches.
What is the length in inches of a simple pendulum whose period s 1 s?
9.5 inches
What factor has the greatest effect on the period of a pendulum?
Assuming the pendulum referred to s asimple pendulum of an arm and a weight the major factors on the period are the local attraction of gravity and the length of the arm.
A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2
If the length of a pendulum increases what does the period of the pendulum do?
The speed (magnitude of the velocity) of a pendulum is greatest when it is at the lowest part of it's swing, directly underneath the suspension.The factors that affect the period of a pendulum (the time it takes to swing from one side to the other and back again) are:# Gravity (the magnitude of the force(s) acting on the pendulum)# Length of the pendulum # (+ minor contributions from the friction of the suspension and air resistance)
How do you predict the period of the pendulum if the length of string was 24cm?
To predict the period of a pendulum, we can use the equation T = 2Ļā(L/g), where T is the period, L is the length of the string, and g is the acceleration due to gravity. Plugging in L = 24cm (or 0.24m) and g = 9.8 m/sĀ², we can calculate the period using this equation.
How does the length of the string affect the period of the pendulum?
Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length. T = 2pi sq root of (length /g) If you wish to clarify physics doubts, please subscribe to my handle @Raj-bi7xp
What is the period of a pendulum on Neptune compared to earth?
equation for time in pendulum: t = 2 * pi * ( sq. root (l / g)) key: t = time elapsed ( total, back and forth ) l = length , from pivot to centre of gravity g = acceleration due to gravity say 1 metre length pendulum on earth @ 9.82 (m/s)/s, t = 2.005 seconds same pendulum on neptune @ 11.23 (m/s)/s, t = 1.875 seconds
Does weight affect the swinging speed of a pendulum?
The period of the pendulum is dependent on the length of the pendulum to the center of mass, and independent from the actual mass.The weight, or mass of the pendulum is only related to momentum, but not speed.Ignoring wind resistance, the speed of the fall of objects is dependent on the acceleration factor due to gravity, 9.8 m/s/s which is independent of the actual weight of the objects.
How does the length of a string affect the number Of times a pendulum will swing back and fourth in 10 seconds?
Yes. Period proportional to (Length)-2 is the fundamental property of the pendulum. The formula for the Period (1 complete swing), T, for a pendulum of length L is: T = 2*pi sqrt (L/g) (Oh for a library of symbols to avoid computer-code abbreviations!) T is in seconds, L in metres, g, the acceleration due to gravity, = 9.8m/s2 So for a given length, it is easy to work out the number of complete swings in 1 minute.
What is the free-fall acceleration in a location where the period of a 0.850 m long pendulum is 1.86 s?
Time period and length of a pendulum are related by: T = 2(pi)(L).5(g).5 so putting in the values and solving for g yields a result of : g = 9.70 ms-2
