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the linearization of f(x) = x^4 + 3x^2 with a = -1 is L(x) = 4 - 10(x+1)

the linearization formula is L(x) = f(a) + f'(a)*(x-a)

when, a = -1

f(a) = (-1)^4 + 3(-1)^2 = 4

f'(x) = 4*x^3 + 6*x

f'(a) = 4(-1)^3 + 6(-1) = -10

so, L(x) = (4) + (-10)*(x-(-1)) = 4 - 10(x+1)

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Q: What is the linearization L of x of the function at a. If f of x equals x to the 4 power plus 3x square a equals negative 1?
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