xyz = t
Divide both sides of the equation by "yz" to find the value of x:
x = t/yz
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If xyz=1, then it is very likely that x=1, y=1, and z=1. So plug these in. 1=logbase1of1, 1=logbase1of1, 1=logbase1of1. You end up with 1=1, 1=1, and 1=1. That's your proof.
T = 3x + 7y; x = 4; y = 6T = 3x + 7y (substitute 4 for x, and 6 for y)T = 3(4) + 7(6) = 12 + 42 = 54
T/y = x/wMultiply each side by 'x':Tw/y = x
no.. x equals 11
x = ab x = 21*37 x = 777