Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
13
If y = 3x +- 1, the derivative with respect to x is y' = 3.
y is 12
Find the derivative of Y and then divide that by the derivative of A
y=3 cos(x) y' = -3 sin(x)
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
(xlnx)' = lnx + 1
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
y=(2x)2 y=2(2x) y=4x
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Y = 36cot(x)Y' = dy/dx36cot(x)= - 36csc2(x)==========
D(y)= sin 2x
sec(x)tan(x)