let y= xsqrt(x) -1
y= x^(3/2) -1 ---- since xsqrt(x) is the same as x^(3/2)
y' = (3/2) x^(3/2-1)
y' = (3/2) x^(1/2)
y'' = (3/2) (1/2) x^(1/2-1)
y'' =(3/2)(1/2) x^(-1/2)
y'' = 3/4x^(1/2)
y'' = 3 / 4sqrt(x)
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the second derivative at an inflectiion point is zero
When the first derivative of the function is equal to zero and the second derivative is positive.
You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.
(x3)'=3x2(x3)''=(3x2)'=6x
she thought she would get points of infliction!