The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of π, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nπ, where n is an integer.
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csc(x) = 0 is the same as 1/sin(x) = 0. One over some other number is never equal to zero (though it is sometimes undefined). Therefore no x exists that satisfies that equation.
Yes of course cosec x is the inverse of sin x by definition in trigonometry sin x=opp. side/hypotenuse cosec x= hypotenuse/opp.side thank u
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points