csc(x) = 0 is the same as 1/sin(x) = 0. One over some other number is never equal to zero (though it is sometimes undefined). Therefore no x exists that satisfies that equation.
Yes of course cosec x is the inverse of sin x by definition in trigonometry sin x=opp. side/hypotenuse cosec x= hypotenuse/opp.side thank u
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
Yes of course cosec x is the inverse of sin x by definition in trigonometry sin x=opp. side/hypotenuse cosec x= hypotenuse/opp.side thank u
d/dx cosec(x) = - cosec(x) * cot(x) so the second derivative or d(d/dx)/dx cosec(x) = [- cosec(x) * d/dx cot(x)] + [ - d/dx cosec(x) * cot(x)] = [- cosec(x) * -cosec^2(x)] + [ - (- cosec(x) * cot(x)) * cot(x)] = cosec(x) * cosec^2(x) + cosec(x)*cot^2(x) = cosec(x) * [cosec^2(x) + cot^2(x)].
Yes.
x = 0 or x = 2
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
0
The only solution to this is x=0.
True because in both equations x = 0 or x = -4
solution: y = 0 x = -1
(x, y) = (-6, 0)
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other