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Q: What is the solution set of the equation x squared minus 3x minus 4 equals 0?

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It is a quadratic equation with one unknown variable, x which has no real roots.

Use the quadratic formula, with a = 1, b = -3, c = 2.

The equation x2 - 5x - 24 = 0 has the two solutions 8 and -3 for x.

The equation 4x + 5 = 2 has the solution 4x = -3 and x = - 3/4 (minus 3/4).

It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3

Related questions

x = 2.1374586088176875 x = -1.6374586088176875

{-1,7}

The equation does not have a real number solution. Using the quadratic formula will give it's conjugate pair complex solution.

There's an equals missing...

i think its 10

(4.25, 0.25) is a solution.

If the 64 has a minus sign, then the solution is x = +/-5 Simplifying gives 4x squared = 100 ie x squared = 25...

X=-3

The value of x is 7

The equation has infinitely many solutions.

It is a quadratic equation and its solutions are: x = -3/2 and x = 3

x equals negative b plus or minus the square root of b squared minus 4bc over 2a

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