x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5
(x + 2)(x - 4)
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
Provided that x- 2 is not zero: 2x3 + x2 - 13x + 6 = 2x3 - 4x2 + 5x2 - 10x - 3x + 6 = 2x2*(x - 2) + 5x*(x - 2) - 3*(x - 2) = (x - 2)*(2x2 + 5x - 3) Therefore, (2x3 + x2 - 13x + 6)/(x - 2) = (x - 2)*(2x2 + 5x - 3)/(x - 2) = 2x2 + 5x - 3 If x = 2 so that x - 2 = 0, then the expression is not defined.
5x - 1 = 24 5x - 1 + 1 = 24 + 1 5x = 25 5x/5 = 25/5 x = 5
x2+5x-24=0(x+8)(x-3)=0x=-8 x=3
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
5x(x - 2)
2x squared - 5x - 3 = (2x +1)(x -3)
(5x - 6)(5x + 6)
Factored, that's (x - 6)(5x + 2) x = 6, -2/5
(x - 1)(5x + 7)
(5x - 2)(x - 5)
(x-1)(x-4)
5x2 + 9x + 13 has no real factors.
x2-5x-36 = (x-9)(x+4) when factored
If: x^2 -5x +6 = 0 then x = 2 or x = 3