Q: Multiply square root 3 by square root 2?

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Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5

The numbers are: (3 +square root of 153) and (3 -square root of 153)

The answer to square root of 9 for example, is 3 and -3... When you multiply 3 times -3 it comes out to be 9

hmm... okay, if I understand you correctly, 2 times the square root of 3 times the square root of 12? = 2(1.73)(3.46) = 11.9716. If you aren't using the approximations, then just simplifying is... [sorry, I can't do the square root sign on the computer...] 2(square root of 3)(square root of 12) = 2(square root of 3)(square root of 4*3) = 4(square root of 3)(square root of 3) = 4(3) = 12!!! HOPE I HELPED!! :-)

It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).

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Depends on the situation. You usually have to multiply numerator and denominator by some number or expression. Examples: 1 / square root of 2 Here, you have to multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3) Here, you have to multiply numerator and denominator by (square root of 2 - square root of 3).

An example may help. If you have the fraction 1 / (2 + root(3)), where root() is the square root function, you multiply top and bottom by (2 - root(3)). If you multiply everything out, you will have no square root in the denominator, instead, you will have a square root in the numerator. If the denominator is only a root, eg root(3), you multiply top and bottom by root(3).

To multiply 2 square root of 2 by 3 square root of 6, simplify each square root separately first: 2 square root of 2 simplifies to 2√2, and 3 square root of 6 simplifies to 3√6. Then, multiply the coefficients (2 and 3) to get 6, and multiply the square roots (√2 and √6) to get √(2x6) = √12. So, the final answer is 6√12.

Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5

The numbers are: (3 +square root of 153) and (3 -square root of 153)

The answer to square root of 9 for example, is 3 and -3... When you multiply 3 times -3 it comes out to be 9

hmm... okay, if I understand you correctly, 2 times the square root of 3 times the square root of 12? = 2(1.73)(3.46) = 11.9716. If you aren't using the approximations, then just simplifying is... [sorry, I can't do the square root sign on the computer...] 2(square root of 3)(square root of 12) = 2(square root of 3)(square root of 4*3) = 4(square root of 3)(square root of 3) = 4(3) = 12!!! HOPE I HELPED!! :-)

It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).

Yes. Multiply both the bottom and top by root 3. Then you have 2 root 3 over two. 2 over 2 simplifies to 1, so the final answer is the square root of 3.

I will use "root" as a symbol for square root. I assume you want to get rid of the square root in the denominator; this will usually bring some square root into the numerator.If you have the square root by itself, or as a factor, multiply numerator and denominator by this square root. Example:3 / root(2) = 3 x root(2) / root(2) x root(2) = 3 x root(2) / 2.If the square root is added or subtracted with something else, multiply with a "complement", as in the following example:1 / root(2) + 5The "complement" is the same expression, but changing the plus sign to a minus sign. Multiply numerator and denominator aby root(2) - 5:root(2) - 5 / (root(2) + 5)(root(2) - 5)= (root(2) - 5) / (2 - 25)= (root(2) - 5) / -23= -(root(2) - 5) / 23

3x^2 = 44 divide both sides by 3; x^2 == 44/3 x = +,- square root of 44/3 write 44 = 4 x 11; x = +,- 2(square root of 11/3) multiply the square root of 11/3 by square root of 3/3; x = +,- (2/3)(square root of 33)

You would go about this question by first specifying whether there are parenthesis around the square root (3/2) or if it looks like (square root 3)/2 Case A would look something like this. 1/(square root of 3/2) in this case you would multiply both the top and bottom by (square root of 3/2). The bottom portion would become (surprisingly!) 3/2. the top portion would be left as (square root of 3/2). Then, because you are dividing by a fraction, the KEEP CHANGE FLIP rule applies. (square root of 3/2) divided by 3/2 would become (square root of 3/2) multiplied by 2/3 which = 2(square root of 3/2)/3. You can then say that 2 is equal to radical 4 and multiply this by the numerator of the other radical, to get radical 12/2 which equals radical 6. Radical 6 over 3 would be the simplified answer. Case B would look something like this. 1/(square root 3)/2 In this case you would multiply both the top and the bottom by (square root of 3). You would get (square root of 3) divided by 3/2. Then KEEP CHANGE FLIP applies again, and it becomes (square root of 3) multiplied by 2/3. This would then equal 2 radical 3 over 3.