2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
2 plus 1-x divided by.
2x+2=x+5 x=3
(-2, 4)
2x + 2 = x + 5Subtract 2 from each side:2x = x + 3Subtract 'x' from each side:x = 3
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
4 + 24 + 16 = 44
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
8x-7 plus 2x equals 6 plus 5x plus 2?
2x + 5 = 13 2x = 8 2x/2 = 8/2 x=4
2 plus 1-x divided by.
2x+2=x+5 x=3
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
(2, 1)
(-2, 4)
2x + 2 = x + 5Subtract 2 from each side:2x = x + 3Subtract 'x' from each side:x = 3
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5