3x - y = 3
y = 2x + 2
Put the value of y in the 1st equation:
3x - y = 3 it will be -->
3x - ( 2x + 2 ) = 3
3x - 2x - 2 = 3
x - 2 = 3
X = 5
Put the value of X in the 2nd equation so as to find the value of Y :
y = 2x + 2
y = 2(5) + 2
y = 10 + 2
Y = 12
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2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
2 plus 1-x divided by.
2x+2=x+5 x=3
(-2, 4)
2x + 2 = x + 5Subtract 2 from each side:2x = x + 3Subtract 'x' from each side:x = 3